2MnO4-(aq) +5 H2O2 (aq) + 6H+(aq) -> 5 O2(g) + 2 (Mn2+(aq) = 8H2O (l)

If a 25.00 ml sample of hydro peroxide required 25.25 ml of .353 M KMNo4 solution to react with all the hydrogen perozide what was the molarity of the hydrogen peroxide solution?

To find the molarity of the hydrogen peroxide solution, you can use the equation:

Molarity of KMnO4 solution x Volume of KMnO4 solution = Molarity of H2O2 solution x Volume of H2O2 solution

In this case, the volume of the KMnO4 solution is 25.25 ml, and the molarity of the KMnO4 solution is 0.353 M. The volume of the H2O2 solution is 25.00 ml. We need to solve for the molarity of the H2O2 solution.

Let's plug in the values into the equation:

0.353 M x 25.25 ml = Molarity of H2O2 solution x 25.00 ml

Now, we can solve for the molarity of the H2O2 solution:

Molarity of H2O2 solution = (0.353 M x 25.25 ml) / 25.00 ml

Calculating this value gives:

Molarity of H2O2 solution = 0.356 M

Therefore, the molarity of the hydrogen peroxide solution is 0.356 M.

see the other post I just did. Are you answer grazing?