I have a fraction problem that involves borrowing and I do not know how to do this. My problem is 11 2/3 - 3 5/6. I know that I need to make the denominator the same so that makes it 11 4/6 - 3 5/6. My 11 needs to go to 10 but I do not know what changes from there. Thank you for your help!
the 5/6 changes to 11/6 because you borrowed 1 or 6/6
Then you subtract (10 4/6 - 3 11/6) to get:
7 7/6
the 1st answer isnt right trust me
10 10/6
11 2/3 = 11 4/6 = 10 10/6
- 3 5/6 = 3 5/6 = 3 5/6
--------------------------
7 5/6
the reason the answer lance gave you is wrong is because when you borrow you have to add the 4/6 and 6/6 because 6/6 is a whole that's borrowing
To solve the fraction problem 11 2/3 - 3 5/6, you correctly identified that you need to make the denominators the same. You converted 11 2/3 to 11 4/6 and kept 3 5/6 as it is.
Then, you need to subtract the two fractions:
10 4/6 - 3 5/6.
Next, to subtract the whole number part, you need to borrow from the 11 to make it 10. When you borrow from the whole number, you need to convert the 1 into fractional form with the same denominator as the fractions in the problem. Since the denominator is 6, we can write 1 as 6/6.
So, the expression becomes:
10 4/6 - 3 5/6 = 10 10/6 - 3 5/6.
Now, to subtract the fractions, keep the denominator the same and subtract the numerators:
10 10/6 - 3 5/6 = 10 - 3 + (10/6 - 5/6).
10 - 3 is 7, and the fractions have the same denominator, so we can simplify further:
7 + (10/6 - 5/6) = 7 + 5/6.
Finally, add the whole number part to the simplified fraction:
7 + 5/6 = 7 5/6.
Therefore, the solution to the fraction problem 11 2/3 - 3 5/6 is 7 5/6.