An 80kg golf hall is struck for a period of0.03s wt a force of 500n.the bal accelerate frm the tree.wat is its final speed.
Impulse = (Force)*(Time)
= momentum change = M*(delta V)
Solve for the speed change delta V. It will be the final speed.
You may have copied the problem incorrectly. A golf ball does not weigh 80 kg. It weighs more like 80 grams
To calculate the final speed of the golf ball, you can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The equation can be written as:
F = m * a
Where:
F = Net force (in Newtons)
m = Mass of the object (in kilograms)
a = Acceleration of the object (in meters per second squared)
In this case, the mass of the golf ball is given as 80 kg. The force applied to the golf ball is 500 N. Therefore, we can rearrange the formula to solve for acceleration:
a = F / m
a = 500 N / 80 kg
a ≈ 6.25 m/s²
Now, to find the final velocity of the golf ball, you can use the formula:
v = u + a * t
Where:
v = Final velocity (unknown)
u = Initial velocity (which is typically 0 when an object is struck from rest)
a = Acceleration (6.25 m/s², as calculated above)
t = Time (0.03 s, given in the question)
Using the values given:
v = 0 + 6.25 m/s² * 0.03 s
v ≈ 0.1875 m/s
Therefore, the final speed of the golf ball is approximately 0.1875 m/s.