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What is the equation for a line in slope intercept form passing through (2,11) and perpenduclar to y =4

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  1. y=4 is a horizontal line, since the slope is zero, i.e.
    y=0x+4.
    A line perpendicular to a horizontal line is vertical.
    The equation for a vertical line is
    x=k
    If the line passes through (2,11), then k=2.
    Therefore the required line is x=2.

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  2. y = 4 is a horizontal line. A line prependicular to it will be vertical, which means that x must be constant. The "slope" m of a vertical line is infinity.

    Therefore the equation for the line is x = 2, regardless of the value of y. Slope-intercept format cannot be used when the slope is infinite.

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