Solve for Matrix D

3 2 -5] [7 0 1
[2 0 8 + D = -4 3 -2]

How to solve this?

The matrices are not recognizable because of the formatting (or lack of it).

Could you repost, using the notations:
Find D in
AxD=C
where

A(3x3)=
3 2 -5
7 0 1
2 0 8

D(3x1)

C(3x1)=
-4
3
-2

etc.

To solve for matrix D, we need to isolate D on one side of the equation.

Given the equation:

[ 3 2 -5 ] [ 7 0 1 ]
[ 2 0 8 ] + D = [ -4 3 -2 ]

The first step is to subtract the given matrix from both sides of the equation:

[ 3 2 -5 ] [ 7 0 1 ] [ 3 2 -5 ] [ 7 0 1 ]
[ 2 0 8 ] + D - [ -4 3 -2 ] = [ 2 0 8 ] - [-4 3 -2 ]

Next, we perform the subtraction operation:

[ 3 2 -5 ] - [ 7 0 1 ] = [ -4 2 -6 ]
[ 2 0 8 ] [ -4 3 -2 ] [ 6 -3 10 ]

Now, we have the equation:

[ -4 2 -6 ] = D

Therefore, the solution for matrix D is:

D = [ -4 2 -6 ]