A stationary roller coaster at the top of its path is 30m about the ground. The car and its passengers have a mass of 400kg. What is the velocity of the car when it reaches the ground lever? The formula for velocity is (Distance/time)

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  1. the gain in Kinetic energy is equal to the loss of potential energy

    1/2 m v^2=mgh
    solve for v

  2. mass cancels out, irrelevant

    m g h = (1/2) m v^2

    2 g h = v^2

    v = sqrt (2 g h)

    v = sqrt (2*9.8*30)

    v = 24.2 m/s

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