I'm trying to figure out the formula for one liter of 1M K2HPO4 (Potassium Phosphate Dibasic). I know the amount of K2HPO4 is 174.18grams and you make it to equal one liter with dH2O, but I can't find where anyone has actually written the amount of dH2O to use. Without actually making it, can some one please help?

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  1. You will NEVER know how much water is used. The way to properly prepare a ? molar solution of anything is to add ? moles to water, swirl to dissolve the solid, then add ENOUGH water (whatever that amount needs to be) to make the final solution exactly 1 L (or any volume of your choosing since you normally use a volumetric flack and you make the water to the mark on the flask).

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