Statistics

Find the minimum sample size that should be chosen to assure that the proportion estimate p will be within the required margin of error, .06. Use a 95% confidence interval and a population proportion of .7. The critical value for a 95% confidence level is 1.96

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  1. Try this formula:
    n = [(z-value)^2 * p * q]/E^2
    = [(1.96)^2 * .7 * .3]/.06^2
    = ? (round to the next highest whole number)

    I'll let you finish the calculation.

    Note: n = sample size needed. Use .7 for p and .3 for q (q = 1 - p). E = maximum error, which is .06 and z-value is 1.96.

    I hope this helps.

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