A 1.5 uF capacitor is connected to a 9.0 V battery. Use PE=1/2C(change in V)^2 to find the energy stored in the capacitor.

C = 1.5*10^-6 farads

V = 9.0 volts

You have the formula. Do the calculation.

The answer, (1/2)CV^2, will be in joules

Well, let me do some quick math... Got it! The energy stored in the capacitor can be calculated using the formula PE = 1/2C(change in V)^2. Plugging in the values, we have:

PE = 1/2(1.5 x 10^(-6)) * (9.0)^2

Now, if you're not a fan of numbers dressed up as exponents, that would be:

PE = 1/2(1.5 microfarads) * (9.0 volts)^2

PE = 0.00000075 farad * 81 joules

And after all the calculations, I must say, the energy stored in the capacitor is just enough to power a hamster on a tiny treadmill for a few microseconds.

To find the energy stored in the capacitor, we can use the formula PE = 1/2C(change in V)^2.

Given:
C (capacitance) = 1.5 uF = 1.5 × 10^(-6) F
change in V (voltage) = 9.0 V

Substituting these values into the formula, we get:
PE = 1/2(1.5 × 10^(-6)) × (9.0)^2

Calculating this expression:
PE = 1/2(1.5 × 10^(-6)) × 81

PE = 0.5 × (1.5 × 10^(-6)) × 81

PE = (0.5 × 1.5 × 81) × 10^(-6)

PE = 60.75 × 10^(-6)

PE = 60.75 µJ

Therefore, the energy stored in the capacitor is 60.75 microjoules (µJ).

To find the energy stored in the capacitor, we can use the formula PE = 1/2C(change in V)^2, where PE represents the stored energy, C represents the capacitance, and (change in V) represents the change in voltage across the capacitor.

In this case, the capacitance is given as 1.5 uF (microfarads), and the change in voltage across the capacitor is 9.0 V.

To solve for the energy stored in the capacitor, we can substitute these values into the formula:

PE = 1/2 * 1.5 uF * (9.0 V)^2

First, we need to convert the capacitance from microfarads (uF) to farads (F). Since 1 microfarad is equal to 1/1,000,000 farads, we can substitute this conversion into the formula:

PE = 1/2 * (1.5 * 10^(-6) F) * (9.0 V)^2

Next, we can calculate the square of the voltage:

PE = 1/2 * (1.5 * 10^(-6) F) * (81 V^2)

PE = (1.5 * 10^(-6) F) * (40.5 V^2)

Finally, we can calculate the value of the energy stored in the capacitor:

PE = 6.075 * 10^(-6) F * V^2

Therefore, the energy stored in the capacitor is 6.075 * 10^(-6) F * V^2.

0.000018