Chemistry

A bag contains a mixture of copper and lead BBs. The average density of the BBs is 9.80 {\rm g/cm^3}. Assuming that the copper and lead are pure, determine the relative amounts of each kind of BB.

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  1. You can do this more easily with a sheet of graph paper but this will have to do since we can't draw pictures.
    11.34...............9.80.........8.93
    d Pb...............d mixture.....d Cu
    |....................|............|
    100%Pb...............?..........0%Pb
    0%Cu.................?........100% Cu

    Look at the above as a graph.
    The total span of density is from 11.34 to 8.93 = 2.41 units.
    From Pb to mixture is 11.34-9.80 = 1.54
    From mixture to Cu is 9.80-8.93 = 0.87
    So % Cu = (1.54/2.41)*100 = ??
    %Pb = (0.87-2.41)*100 = ??
    Check my thinking.

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  2. I'm not sure you got the lead part right, whats simpler is once you get the copper do 1-copper answer to find the lead as the bb's are mixed together (must add up to 100%)

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