college algebra

find the inverse of log5(2x+1)=g(x)

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asked by danny
  1. Is that log to base 5 or log [5(2x+1)] ?

    Assuming that you mean base 5,

    5^g = 2x +1
    x = [5^g -1]/2

    which can be written,
    g^-1(x) = [5^g -1]/2
    where g^-1(x) is the inverse function of g(x)

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    posted by drwls

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