statistics

A 95% confidence interval for a population mean was reported to be 23,100 to 24,900. If the sample standard deviation is 5,808.26, what sample size was used in this study?

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  1. Formula:
    CI95 = mean + or - (1.96)(sd)/√n

    Mean = (23100 + 24900)/2 = 24000
    Standard deviation = 5808.26

    CI95 = 24000 + or - 900 --> gives you confidence interval of 23100 to 24900.

    Therefore:
    900 = (1.96)(sd)/√n
    900 = (1.96)(5808.26)/√n

    Solve for n. Round n to whole number.

    I hope this will help.

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