How do I solve for the missing letters in the following:?
ABCD
X 4
______
DCBA
(the 4 is listed under the D and it appears to be done as a mult. problem?
There is no "=" sign anywhere, so there is nothing to "solve". Anything could go in the blank. You need to reqrite it in a clearer manner. Use the / sign for division and to separate denominators, and use * instead of X for multiplication. And don't forget the = sign, wherever that goes.
Realizing that ABCD = DCBA may be the clue you need to solve the intended question.
ABCD * 4 = DCBA
That statement cannot be true since it implies 4 = 1.
A correct statement would be
ABCD * 4 = 4 DCBA
http://mathforum.org/library/drmath/view/57954.html
You should have explained that ABCD is not, in your question, the product of A, B, C and D. That is the usual algebraic interpration. It is a four-digit number, with letters representing the digiys.
BobPursley has found your answer.
2178 x 4 = 8712
http://mathforum.org/library/drmath/view/57954.html gives you three of the digits: 2, 1 and 8. The fourth (7) was obtained by trial and error.
How do I solve for the missing letters in the following:?
ABCD
...4
DCBA
What does each letter stand for?
1--A must be 1 or 2
2--If A = 1, 4D = 1 cannot be so A = 2.
2BCD
...x4
DCB2
3--D can be 3 or 8 to give an A = 2
4--If D = 3, 4A cannot be 3 so D = 8.
2BC8
...x4
8CB2
5--C can be 1, 3, 5, 6, 7, or 9.
6--4C + 3 = 10 + B
....................C....1....3....5....6....7....9
....................B....7....5....3....7....1....9
....................R....0....1....2....2....3....3 R = remainder
4B + R = C....8....1....4....0....7....9
..........................X....X....X....X....Y....X
7--Only C = 7 results in the two C's being equal. (B = 9 from C = 9 would make 4B greater than 10 giving the answer 5 digits.)
8--Therefore, C = 7 and B = 1 for
2178
...x4
8712
i need some help with my math can you help thank you if you find someone from MINDY
i just love math
A=2
B=1
C=7
D=8