A student placed 17.0 g of glucose (C6H1206) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.-ml mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 50.0-L sample of this glucose solution was diluted to 0.500L . How many grams of glucose are in 100.ml of the final solution?

Question

A student placed 17.0 g of glucose (C6H1206) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.-ml mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 50.0-L sample of this glucose solution was diluted to 0.500L . How many grams of glucose are in 100.ml of the final solution?

Answer 1

You have made a typo; it doesn't make sense as is. I think you intended 50.0-L sample to be a 50.0mL sample was diluted to 0.500 L.

Answer 2

To find the number of grams of glucose in 100 mL of the final solution, we need to calculate the concentration of glucose in the solution and then use that concentration to determine the mass.

First, let's calculate the concentration of glucose in the original solution. The initial solution was made by dissolving 17.0 g of glucose in enough water to reach the 100 mL mark. Therefore, the concentration of glucose in the original solution is:

Concentration = (mass of glucose / volume of solution) * 100

Concentration = (17.0 g / 100 mL) * 100 = 17.0 g/ 100 mL

Next, we need to determine the final concentration of glucose after the 50.0 L sample is diluted to 0.500 L.

This can be done using the dilution formula:

C1V1 = C2V2

Where:
C1 = initial concentration
V1 = initial volume
C2 = final concentration
V2 = final volume

Plugging in the values:
(17.0 g/ 100 mL) * V1 = C2 * (0.500 L)

We know that the final volume (V2) is 0.500 L and we need to solve for C2 (the final concentration). We can rearrange the equation to solve for C2:

C2 = (17.0 g / 100 mL) * V1 / (0.500 L)

Now, we need to calculate V1 (the volume of the original solution used to make the dilution), which can be found using the equation:

V1 = (C2 * V2) / C1

Plugging in the values:
V1 = [(17.0 g / 100 mL) * 0.500 L] / (17.0 g / 100 mL)

V1 = 0.500 L

Now that we have the final concentration (C2) and the volume of the original solution used (V1), we can calculate the number of grams of glucose in 100 mL of the final solution:

Mass = concentration * volume

Mass = (17.0 g / 100 mL) * 100 mL = 17.0 g

Therefore, there are 17.0 grams of glucose in 100 mL of the final solution.

You have made a typo; it doesn't make sense as is. I think you intended 50.0-L sample to be a 50.0mL sample was diluted to 0.500 L.

askjakhd

25.0ml

To find the number of grams of glucose in 100 mL of the final solution, we need to calculate the concentration of glucose in the solution and then use that concentration to determine the mass.