Redox reaction of cl2 --> cl ion and clo2-
I split it up into two half reactions cl2-->2cl- and cl2-->2clo2-
And you are having trouble with what?
I am not able to cancel out all the electrons
Post your work and I'll try to find the error.
To determine the redox reaction for the transformation of Cl2 to Cl- and ClO2-, you correctly split it into two half-reactions.
The half-reaction for the reduction of Cl2 to Cl- can be written as follows:
Cl2 + 2e- → 2Cl-
In this reaction, Cl2 gains two electrons (reduction) to form two Cl- ions.
The half-reaction for the oxidation of Cl2 to ClO2- can be written as follows:
Cl2 → 2ClO2- + 2e-
In this reaction, Cl2 loses two electrons (oxidation) to form two ClO2- ions.
By combining these two half-reactions, we can obtain the balanced redox reaction:
2Cl2 + 4e- → 4Cl- + 2ClO2-
In this final redox reaction, two Cl2 molecules react to form four Cl- ions and two ClO2- ions.