Math - Real number system

Solve the following equation in the real number system. Please show all of your work.

x^4 + 6x^3 + x^2 - 24x - 20 = 0

Help!!!!

  1. 👍 0
  2. 👎 0
  3. 👁 165
  1. Let f(x)=x^4+6x^3+x^2-24x-20
    Real roots are looking for among
    +-1,+-2,+-4,+-5,+-10,+-20
    f(-1)=1-6+1+24-20=0
    Divide f(x) by (x+1):
    f(x)=(x+1)(x^3+5x^2-4x-20)
    Let g(x)=x^3+5x^2-4x-20
    g(-5)=-125+125+20-20=0
    Divide g(x) by (x+5):
    g(x)=(x+5)(x^2-4)

    f(x)=(x+1)(x+5)(x+2)(x-2)

    1. 👍 0
    2. 👎 0
  2. what is 2/5 in the real number system

    1. 👍 0
    2. 👎 0

Respond to this Question

First Name

Your Response

Similar Questions

  1. Algebra

    Create a system of equations that includes one linear equation and one quadratic equation. Part 1. Show all work to solving your system of equations algebraically. Part 2. Graph your system of equations, and show the solution

    asked by Sally on June 9, 2016
  2. Math check please

    1. Solve the system of equations y=2x^2-3 y=3x-1 a)no solution b)(-1/2,5),(2,-5/2) c)(-1/2,-5/2),(2,5)**** d)(1/2,5/2),(2,5) 2. How many real number solutions are there to the equation 0=-3x^2+x-4? a)0 ***** b)1 c)2 d)3 3.solve

    asked by Kendra on March 19, 2015
  3. ALGEBRA CHECK ANSWERS

    Solve each equation by graphing the related function. If the equation has no real-number solution, write no solution. NOTE: when I write + it has a minus on the bottom too x^2+7=0 a. x= +7 b. x = +3.5 c. x= 0 d. no solution ***

    asked by a on April 4, 2017
  4. Math

    Lesson 8: Systems of Linear and Quadratic Equations Check my work 1. Solve the system of equations. y = 2x^2 - 3 y = 3x - 1 a. no solution b. (-1/2, 5), (2, -5/2) c. (-1/2, -5/2), (2,5)*** d. (1/2, 5/2), (2, 5) 2.how many real

    asked by Gameknight on March 19, 2020
  5. algebra

    Solve the equation using the zero-product property. -9n(5n-5) a. -1/9, 1 b. 0,1***** c. -1/9,-1 d. 0,-1 Use the quadratic formula to solve the equation. if necessary, round to the nearest hundredth. x^2-6=x a. x=2,3 b. x=-2,3

    asked by frank on May 14, 2018
  1. Algebra

    1.Solve the system of equations. y = 2x^2 - 3 y = 3x - 1 a. no solution b. (-1/2, 5), (2, -5/2) c. (-1/2, -5/2), (2,5) d. (1/2, 5/2), (2, 5) 2.how many real number solutions does the equation have 0 = -3x^2 + x - 4 a. 0 b. 1 c. 2

    asked by Gameknight on March 19, 2020
  2. ALGEBRA 1!PLZ HELP!

    Use the Substitution method to solve the system of equations. y - 2x = -5 3y - x = 5 Solve the first equation for y. y = 2x-5 Substitute that for y in the second equation and solve for x. Then use the value of x to substitute back

    asked by SANDRO! on November 6, 2006
  3. Algebra

    Consider the equation 4x^2 – 16x + 25 = 0. (a) Show how to compute the discriminant, b^2 – 4ac, and then state whether there is one real-number solution, two different real-number solutions, or two different imaginary-number

    asked by Pamela on July 7, 2009
  4. algebra

    Solve using the elimination method. Show your work. If the system has not solution or an infinite number of solutions, state this. -2x-8y=-42 -4x+6y=-18

    asked by Ann on July 3, 2012
  5. math

    1. Solve for the indicated letter D=4e, for e The solution is e= 2. G(x) = 6/(6-5x) Choose the correct domain below {x|x is a real number and x ≠0} {x|x is a real number and x≠6/5} {x|x is a real number and x≥6/5} {x|x is a

    asked by Letty on September 8, 2009
  6. Algebra HELP

    how to solve this equation in the real number system: 2x^(3) + 3x^(2) + 2x + 3 = 0 steps please

    asked by Amy on November 14, 2010

You can view more similar questions or ask a new question.