determine the first 4 terms of the sequence tn=-n^2+7
t(n)=-n^2+7
for n=1
t(1)=-(1)^2+7=-1+7=6
t(2)=-(2)^2+7=-4+7=3
...
I'll leave the other two to you for practice.
for n=1
t(1)=-(1)^2+7=-1+7=6
t(2)=-(2)^2+7=-4+7=3
...
I'll leave the other two to you for practice.