: what is the Ka of butanoic acid whose pka is4.82?
show workkkk please
pH = -log(H^+) and
pOH = -log(OH^-).
Likewise,
pKa = -log(Ka), so
4.82 = -log Ka
log Ka = -4.82
Ka = 1.51E-5
To find the Ka (acid dissociation constant) of butanoic acid from its pKa value, we can use the equation:
pKa = -log10(Ka)
First, let's convert the pKa value to Ka. Since the equation is in terms of logarithms, we need to take the antilog using the inverse function of the logarithm, which is 10 raised to the power of the negative pKa value:
Ka = 10^(-pKa)
Now, substitute the given pKa value into the equation:
Ka = 10^(-4.82)
Using a calculator, evaluate 10 raised to the power of -4.82 to find the value of Ka:
Ka ≈ 1.43 × 10^(-5)
Hence, the value of Ka for butanoic acid is approximately 1.43 × 10^(-5).