how much force is necessary to stop a 2500 pound car from rolling down a 40degree slope
M g sin40.
If you use M g = 2500 lb, the answer will be in pounds.
If you want it in Newtons, use a mass of M = 1136 kg, with g = 9.8 m/s^2.
To calculate the force needed to stop a car from rolling down a slope, we need to consider the weight of the car, the angle of the slope, and the force of gravity. Here's how you can calculate it:
1. Convert the weight of the car from pounds to Newtons. Since weight is a force, we need to use the metric unit of force. 1 pound is approximately equal to 4.448 Newtons. So, 2500 pounds can be converted to Newtons by multiplying it by the conversion factor:
Weight in Newtons = 2500 pounds * 4.448 N/pound
2. Determine the component of the weight acting parallel to the slope. The weight can be broken down into two components: the force due to gravity acting straight down (mg), and the component of the weight parallel to the slope (mg * sin θ). Since we know the angle of the slope is 40 degrees, we can use the equation:
Force parallel to the slope = Weight in Newtons * sin(40°)
3. The force necessary to stop the car from rolling down the slope is equal to the force parallel to the slope. So, that would be:
Force required = Force parallel to the slope
By plugging in the values obtained from steps 1 and 2, you should be able to calculate the force required to stop the car.