Trigonometry

Solve:

2cos^2 theta - 3cos theta+ 1= 0

interval [0, 2ð)

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  1. let z = cos theta
    then
    2 z^2 -3 z + 1 = 0
    (2z-1)(z-1) = 0
    z = 1/2 or z = 1
    cos theta = 1/2 gives theta = 60degrees or pi/3 radians and also -60
    cos theta = 1 means 0 or 360

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    posted by Damon

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