Find an equation of the line containing pair of points
(1/6, 1/3) and (5/6, 3)
I can't seem to figure out the slope right, which apparently is 5. How does one get a five slope out of all these fractions?!!!
To find the slope 3-1/3 = 8/3 over
5/6 - 1/6 = 4/6 = 2/3
What am I doing wrong?
so the numerator is 8/3 and the denominator is 2/3
then (8/3) / (2/3)
= (8/3)(3/2) = 4 , not 5
equation: y = 4x + b
plug in (1/6, 1/3)
1/3 = 2/3 + b
b = -1/3
y = 4x - 1/3
Hi,
I got four also, but the program I ran gave me the answer as 5x +7/6. What bothers me about the program is we have to take tests with the program and the problems don't work out to be what our workbook says.
Thanks for your feedback.
To find the slope of a line containing two points, you use the formula:
slope = (y₂ - y₁) / (x₂ - x₁)
Let's use the given points to find the slope:
Point 1: (1/6, 1/3)
Point 2: (5/6, 3)
Now, substitute the coordinates into the slope formula:
slope = (3 - 1/3) / (5/6 - 1/6)
First, let's simplify the numerator:
slope = (9/3 - 1/3) / (5/6 - 1/6)
slope = (8/3) / (4/6)
slope = (8/3) / (2/3)
To divide by a fraction, you can multiply by the reciprocal (flip the fraction):
slope = (8/3) * (3/2)
slope = 24/6
slope = 4
So, the slope of the line passing through the points (1/6, 1/3) and (5/6, 3) is indeed 4, not 5. It seems like there might have been an error in your calculation when simplifying fractions.