what is the balanced equation of NaHCO3+CH3OOH---->H2CO3+NaCH3COO
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You should have written
NaHCO3 + CH3COOH ==> and the eqution is balanced .
To balance the equation NaHCO3 + CH3OOH → H2CO3 + NaCH3COO, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
1. Start by counting the number of atoms on each side of the equation:
NaHCO3: 1 Na, 1 H, 1 C, 3 O
CH3OOH: 1 C, 4 H, 2 O
H2CO3: 1 C, 3 O
NaCH3COO: 1 Na, 2 C, 4 H, 2 O
2. We can start balancing with the simplest elements: Na and C.
There is 1 Na on the left and 1 Na on the right, so the Na atoms are already balanced.
There is 1 C on the left and 2 C on the right, so we need to put a coefficient of 2 in front of NaHCO3:
2 NaHCO3 + CH3OOH → H2CO3 + NaCH3COO
3. Now let's balance the H and O atoms.
On the left, there are 2 H atoms from NaHCO3 and 4 H atoms from CH3OOH, totaling 6 H atoms.
On the right, there are 4 H atoms in NaCH3COO.
To balance the H atoms, we need to put a coefficient of 3 in front of NaCH3COO:
2 NaHCO3 + CH3OOH → H2CO3 + 3 NaCH3COO
Now that we have balanced the H atoms, let's look at the O atoms.
On the left, there are 6 O atoms from NaHCO3 and 2 O atoms from CH3OOH, totaling 8 O atoms.
On the right, there are 3 O atoms in H2CO3 and 6 O atoms in NaCH3COO, totaling 9 O atoms.
To balance the O atoms, we need to put a coefficient of 4 in front of CH3OOH:
2 NaHCO3 + 4 CH3OOH → H2CO3 + 3 NaCH3COO
Final balanced equation:
2 NaHCO3 + 4 CH3OOH → H2CO3 + 3 NaCH3COO