a model submarine that is 15 inches long and 3inches tall.the full size submarine was 60 feet tall.how long was the full size submarine?

15/3 = x/60

Cross multiply and solve for x.

To find the length of the full-size submarine, we can set up a proportion using the given information.

Let's assign variables to the given lengths:
Length of the model submarine: l1 = 15 inches
Height of the model submarine: h1 = 3 inches
Height of the full-size submarine: h2 = 60 feet

We need to find the length of the full-size submarine: l2 = ?

Since the proportions are equal, we have:

l1 / h1 = l2 / h2

Now we can substitute the known values and solve for l2:

15 inches / 3 inches = l2 / 60 feet

To solve this equation, we need to convert the units to be the same. Let's convert inches to feet:

15 inches = 15/12 feet = 1.25 feet

Substituting the values into the equation:

1.25 feet / 3 inches = l2 / 60 feet

To simplify, let's convert 3 inches to feet:

3 inches = 3/12 feet = 0.25 feet

Substituting again:

1.25 feet / 0.25 feet = l2 / 60 feet

Now we can solve for l2:

(1.25 feet / 0.25 feet) * 60 feet = l2

Simplifying:

5 * 60 feet = l2

l2 = 300 feet

Therefore, the full-size submarine was 300 feet long.