# algebra

When factored completely 4x^2y-8x^2y^2=2xy(2x-4xy+3y)

1. 👍 0
2. 👎 0
3. 👁 67
1. correct

1. 👍 0
2. 👎 0
posted by Reiny

## Similar Questions

1. ### algebra

When factored completely 4x^2y-8x^2y^2=2xy(2x-4xy+3y)

asked by stellalue on May 27, 2011
2. ### algebra

When factored completely, 4x^2y - 8x^2y^2 + 6xy^2 = 2xy(2x - 4xy + 3y). true or false

asked by tracy on October 19, 2011
3. ### pre-cal

Use Pascal's triangle to expand the expression. (x − y)5 so I tried to work this out: (x-y)^5 = [(x-y)(x-y)][(x-y)(x-y)](x-y) (x-y)^2 = (x-y)(x-y) = x^2 - 2xy + y^2 x^2 - 2xy + y^2)(x^2 - 2xy + y^2) = x^4 -4x^3y + 6x^2y^2 -

asked by James on August 12, 2015
4. ### Math

Can 2xy - y - 1 be factored out? How? about all you can do is take the common y out of the first two terms; that in itself is not much help. dont know if this is rite or not..but just a guess.. assuming 2xy - y - 1 = 0 2xy - y = 1

asked by Sarah on August 15, 2007
5. ### Calculus

Consider the equation: x^2 - 2xy + 4y^2 = 64 Write an expression of the slope of the curve at any point. (y^p)= y prime My work 2x - 2(xy^p + y) + 8yy^p = 0 2x -2xy^p - 2y + 8yy^p = 0 -2xy^p + 8yy^p = 2y -2x factored out y^p and

asked by Anonymous on October 29, 2008
6. ### Algebra 2

Well I'm curently taking this class as a sophmore and have taken geometry freshmen year of high school and also I am taking physics at the same time and in math class when I'm asked to factor i go absolutley nuts because guessing

asked by HELP ME! on May 8, 2009
7. ### college implicit HELP!

I WANNA KNOW I'M DOING RIGHT. Find the slope of the tangent line to the curve √(3x+2y) + √(4xy)=11.6 at the point (6,4). THAT WHAT I DID: (3x+2y)^1/2+(4xy)1/2=11.6 next step: 1/2(3x+2y)^-1/2*y'+1/2(4xy)*y=0 y'= -(3x+2y)/(4xy)

asked by josephine on March 1, 2012
8. ### math

(4xy+2xy)to the power of two

asked by thaby on February 18, 2017
9. ### math

10x+5y^2+2xy-4y^2+4xy-x3=

asked by lexi on October 30, 2008
10. ### Math

(2xy^2+16x^2y-20xy+8) / (4xy)

asked by christine on March 7, 2016

More Similar Questions