physics

The tires of a car make 58 revolutions as the car reduces its speed uniformly from 92 to 33 . The tires have a diameter of 0.86 .

What was the angular acceleration of the tires?

If the car continues to decelerate at this rate, how much more time is required for it to stop?

  1. 👍 0
  2. 👎 0
  3. 👁 366
asked by juana
  1. 1.C = pi*D = 3.14*0.86 = 2.7Ft.

    d = 58rev * 2.7Ft/rev = 156.6Ft.

    Vo = 92mi/h * 5280Ft/mi *(1h/3600s)=134.9Ft/s. = Inital velocity.

    Vf = 33mi/h * 5280Ft/mi * (1h/3600s)=48.4Ft/s. = Final velocity.

    To = d/Vo = 156.6Ft / 134.9Ft/s = 1.16s.

    Tf = 156.6Ft / 48.4Ft/s = 3.23s.

    a = (Vf-Vo)/(Tf-To)
    a = (48.4-134.9) / (3.23-1.16) = -41.8Ft/s^2, Linear.

    a=-41.8Ft/s^2 * 6.28rad/2.7Ft=
    -97.2rad/s^2, Angular.

    2. Vf = Vo + at = 0.
    48.4 -97.2t = 0,
    t = 0.50s.

    1. 👍 0
    2. 👎 0
    posted by Henry

Respond to this Question

First Name

Your Response

Similar Questions

  1. physics help!

    The tires of a car make 63 revolutions as the car reduces its speed uniformly from 94.0 km/h to 58.0 km/h. The tires have a diameter of 0.88 m. What was the angular acceleration of each tire? And If the car continues to decelerate

    asked by Anonymous on March 25, 2010
  2. physics help please!!!

    The tires of a car make 63 revolutions as the car reduces its speed uniformly from 94.0 km/h to 58.0 km/h. The tires have a diameter of 0.88 m. What was the angular acceleration of each tire? And If the car continues to decelerate

    asked by Anonymous on March 26, 2010
  3. Trigonometry

    The tires on a car have radius 14 inches. Find the angular speed of the car tire in revolutions per second when it is traveling 70 mph. Find the angular speed at 80 mph. The tires on a car are 15 inches. Find the linear speed of

    asked by Will on January 21, 2012
  4. physics

    A car initially traveling at 31.0 m/s undergoes a constant negative acceleration of magnitude 2.00 m/s2 after its brakes are applied. (a) How many revolutions does each tire make before the car comes to a stop, assuming the car

    asked by Kelsey on March 27, 2010
  5. Physics

    A car initially traveling at 33.4 m/s undergoes a constant negative acceleration of magnitude 1.80 m/s2 after its brakes are applied. (a) How many revolutions does each tire make before the car comes to a stop, assuming the car

    asked by Ed on November 28, 2009
  6. Physics

    A car initially traveling at 33.4 m/s undergoes a constant negative acceleration of magnitude 1.80 m/s2 after its brakes are applied. (a) How many revolutions does each tire make before the car comes to a stop, assuming the car

    asked by Ed on November 28, 2009
  7. physic

    Hi!Need help please. Question:A car initially traveling at 24.0 m/s undergoes a constant negative acceleration of magnitude 2.10 m/s2 after its brakes are applied. (a) How many revolutions does each tire make before the car comes

    asked by Chan on November 14, 2009
  8. physics

    An automobile traveling at 50.0 km/h has tires of 100.0 cm diameter. (a) What is the angular speed of the tires about their axles? 1 rad/s (b) If the car is brought to a stop uniformly in 25.0 complete turns of the tires (without

    asked by Joey on January 5, 2011
  9. PHYSICS

    The driver of a car traveling at 25.0 m/s applies the brakes and undergoes a constant negative acceleration of magnitude 2.50 m/s2. How many revolutions does each tire make before the car comes to a stop, assuming that the car

    asked by Taylor on January 15, 2015
  10. physics

    a car traveling at 30.0m/s undergoes a constant negative accerleration of magnitude of 2.00m/s^2 when the brakes are applied. how many revolutions does each tire make before the car comes to a complete stop,assuming thaat the car

    asked by nay on February 23, 2009

More Similar Questions