how do you calculate the quantity of heat gained or lost?
0.60 mol of steam condenses at 100°C
mass x heat vaporization. You must make sure that the mass and the heat vap are in the same units.And if you are condensing steam the heat will be lost from the steam.
Now I get it, thank you so much!
To calculate the quantity of heat gained or lost during a phase change, you can use the formula:
Q = n * ∆H
where Q represents the heat gained or lost, n is the amount of substance undergoing the phase change (in moles), and ∆H is the molar enthalpy change associated with the phase change.
In this case, we know that 0.60 mol of steam condenses at 100°C. Condensation is considered a phase change from gas to liquid. The molar enthalpy of vaporization (∆H_vap) for water is approximately 40.7 kJ/mol.
Now we can calculate the heat gained or lost:
Q = n * ∆H_vap
Q = 0.60 mol * 40.7 kJ/mol
By multiplying these values, we get:
Q = 24.42 kJ
Therefore, the quantity of heat gained or lost when 0.60 mol of steam condenses at 100°C is 24.42 kJ.