Carbon disulfide is produced by the reaction of carbon and sulfur dioxide.
5C(s) +2 SO2(g) ---------> CS2(g) + 4CO(g)
How many moles of CO would be made if you started with 10 moles of C?
calculate the volume of sulfur dioxide produced when 27.9 mL O2 reacts with carbon disulfide to produce carbon dioxide and sulfur dioxide at STP
0.00186 L of SO2
To find the number of moles of CO produced, we can use the stoichiometry of the balanced equation. According to the balanced equation:
5 moles of carbon (C) react to produce 4 moles of carbon monoxide (CO).
Therefore, the stoichiometric ratio between C and CO is 5:4.
If you start with 10 moles of C, you can use this ratio to calculate the moles of CO produced.
Moles of CO = (moles of C) x (moles of CO/moles of C)
Moles of CO = 10 moles x (4 moles/5 moles)
Moles of CO = 8 moles
Therefore, if you start with 10 moles of C, you would produce 8 moles of CO.
To determine the number of moles of carbon monoxide (CO) produced when starting with 10 moles of carbon (C), we can use the stoichiometry of the balanced chemical equation.
The balanced equation provided is:
5C(s) + 2SO2(g) → CS2(g) + 4CO(g)
From the equation, we can see that for every 5 moles of carbon, 4 moles of carbon monoxide (CO) are produced.
Therefore, to calculate the number of moles of CO produced when starting with 10 moles of C, we can use a proportion:
(4 moles CO / 5 moles C) = (x moles CO / 10 moles C)
Let's solve for x:
Cross-multiplying the equation gives us:
4 moles CO * 10 moles C = 5 moles C * x moles CO
40 moles CO = 5x moles CO
Dividing both sides by 5:
40 moles CO / 5 = x moles CO
x = 8 moles CO
Therefore, if you start with 10 moles of carbon (C), you would produce 8 moles of carbon monoxide (CO) according to the given reaction.