A rock is dropped into a well. Five Seconds later a splash is heard. Calculate the depth of the well(assume the time for sound of the splash to reach you is too small to consider.)

how can i calculate the depth of the well if the only thing that's given is the time?

g = 9.8 m/s^2 , the acceleration

the initial speed, vo is 0
call the initial distance down, xo = 0
then v, the speed down is 0 + 9.8 t
and x, the distance down is
0 + 9.8 t +(1/2)(9.8) t^2

48 ft.

To calculate the depth of the well, you can use the equation of motion for free fall. The equation is:

h = (1/2)gt^2

Where:
h is the height or depth of the well,
g is the acceleration due to gravity (approximately 9.8 m/s^2),
t is the time it took for the stone to fall.

In this case, the time t is 5 seconds. So, we can plug this value into the equation:

h = (1/2)(9.8)(5)^2
= (1/2)(9.8)(25)
= 122.5 meters

Therefore, the depth of the well is 122.5 meters.