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math
the problem is 2cos^2x + sinx1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is what i've done so far: 2cos^2x+sinx1=0 2cos^2x1+sinx=0 cos2x + sinx =0 1  2sin^2x + sinx = 0
asked by alex on April 7, 2008 
Precalculus
Please help!!!!!!!!!!! Find all solutions to the equation in the interval [0,2π). 8. cos2x=cosx 10. 2cos^2x+cosx=cos2x Solve algebraically for exact solutions in the interval [0,2π). Use your grapher only to support your
asked by Anonymous on January 3, 2013 
PreCalculus
Find all solutions to the equation in the interval [0, 2pi) cos4xcos2x=0 So,this is what i've done so far: cos4xcos2x=0 cos2(2x)cos2x (2cos^2(2x)1)(2cos^2(x)1) No idea what to do next.
asked by Maria on March 19, 2012 
Math Help
Hello! Can someone please check and see if I did this right? Thanks! :) Directions: Find the exact solutions of the equation in the interval [0,2pi] cos2x+sinx=0 My answer: cos2x+sinx=cos^2xsin^2x+sinx =1sin^2xsin^2x+sinx
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trig
find the exact solutions 2cos^2x+3sinx=0 the way it stands, that is a "nasty" question. Are you sure the second term isn't 2sin(2x) ? no, its as i wrote it. then it's got me stymied, I must be missing something rather obvious,
asked by Devon on April 16, 2007 
Trig
Verify the identity: tanx(cos2x) = sin2x  tanx Left Side = (sinx/cosx)(2cos^2 x 1) =sinx(2cos^2 x  1)/cosx Right Side = 2sinx cosx  sinx/cosx =(2sinxcos^2 x  sinx)/cosx =sinx(2cos^2 x 1)/cosx = L.S. Q.E.D.
asked by Ashley on April 14, 2007 
Trigcheck answer
Solve the equation of the interval (0, 2pi) cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came up with cos²x=1cos²x Ended up with 2cos²x=1 Would the answer be cos²x=1/2???
asked by Brian on April 15, 2009 
circular (trigonometric) functions
hi, i need help solving this trigonometric equation: sinx+3cosx=0 i don't know what to do as i can't just diviide the two to create tanx which is what i have been doing in previous questions... yes, you are on the right track sinx
asked by elle on April 14, 2007 
Trig.
Can someone please help me with this? Find all solutions to the equation in the interval [0,2pi) cos2x=sinx I know I have to use some sort of identity, but I have no idea how to go about to solve this.
asked by mary on February 27, 2010 
Maths  crazy maths question which involves graphi
This is a question that involves graphing although I'm not very good at it especially Trigonometric Functions >_< a) Find the equation of the tangent to the curve y = sinx at the origin For part (a) I've already found the equation
asked by Anonymous on July 20, 2008