What is the amount of potential energy gained by. 30 grams of Hg as it melts?
To find the amount of potential energy gained by 30 grams of Hg (mercury) as it melts, you need to know the specific heat capacity (C) and the heat of fusion (ΔHfus) of mercury.
The specific heat capacity (C) is the amount of heat energy required to raise the temperature of a substance by 1 degree Celsius (or 1 Kelvin). The heat of fusion (ΔHfus) is the amount of heat energy required to convert a substance from a solid to a liquid state without changing its temperature.
Unfortunately, I don't have the exact values for the specific heat capacity and heat of fusion of mercury. However, I can guide you on how to calculate the potential energy gained during the phase transition from solid to liquid.
The formula to calculate the energy gained during a phase transition is:
Q = m × ΔHfus
Where:
Q is the amount of heat energy gained or lost
m is the mass of the substance
ΔHfus is the heat of fusion
First, you need to convert the mass of mercury from grams to kilograms by dividing it by 1000. In this case, 30 grams of mercury is equivalent to 0.03 kilograms.
Next, multiply the mass (m) by the heat of fusion (ΔHfus) to calculate the energy gained (Q).
Afterwards, you will have the amount of heat energy gained when 30 grams of mercury melts.