How much energy (in joules) is contained in one mole of photons (electromagnetic quanta) of frequency 2.3E+19 Hz?
E = hf*6.022E23
thanks, now do u know the units to this problem
E is in joules. In this case it's for a mole and you might want to call it joules/mol.
To calculate the energy of one photon, you can use the equation:
E = hf
Where:
E is the energy of the photon (in joules)
h is Planck's constant (6.62607015 × 10^-34 J·s)
f is the frequency of the photon (in Hz)
To find the energy contained in one mole of photons, we need to determine the number of photons in one mole. This can be done using Avogadro's number (6.02214076 × 10^23 mol^-1), which represents the number of entities (atoms, molecules, or in this case, photons) in one mole.
First, we calculate the energy of one photon:
E = (6.62607015 × 10^-34 J·s) × (2.3 × 10^19 Hz)
E ≈ 1.52326733 × 10^-14 J
Next, we multiply this energy by Avogadro's number to find the energy in one mole of photons:
Energy in one mole of photons = (1.52326733 × 10^-14 J) × (6.02214076 × 10^23 mol^-1)
Energy in one mole of photons ≈ 9.17454015 × 10^9 J
Therefore, there is approximately 9.17454015 × 10^9 joules of energy in one mole of photons with a frequency of 2.3 × 10^19 Hz.