Boyle's Law says that the volume of a gas varies inversely with the pressure. When the volume of a certain gas is 4L , the pressure is 165kPa (kilopascals). What is the volume when the pressure is 60kPa?
V1P1=V2P2
solve for V2
To solve this problem using Boyle's Law, we can set up the formula:
P1 * V1 = P2 * V2
where P1 and V1 are the initial pressure and volume, and P2 and V2 are the final pressure and volume.
Given that the initial volume is 4L and the initial pressure is 165kPa, we can write:
165kPa * 4L = 60kPa * V2
To find V2, we can rearrange the equation and solve for it:
V2 = (165kPa * 4L) / 60kPa
To compute this, we can divide 165 by 60, and multiply the result by 4:
V2 = (2.75) * (4L)
V2 = 11L
Therefore, when the pressure is 60kPa, the volume of the gas is 11L.