A rectangular garden plot is to be enclosed with 40 meters of fences and the area of the garden is a function of the demensions of the recangle.
What is the question?
Triangular gardens ABC and xyz are similar a=21ft an=7ft andxy=14ft what is the length of xyz
To find the dimensions of the rectangular garden plot, we can use the fact that the perimeter of a rectangle is the sum of all its sides. In this case, we are given that the garden plot is enclosed with 40 meters of fences.
Let's assume the length of the garden plot is L and the width is W.
The perimeter of the rectangle can be expressed as:
P = 2L + 2W
We know that the perimeter is given as 40 meters, so we can write the equation:
40 = 2L + 2W
Next, we can solve this equation for one of the variables in terms of the other. Let's solve for L:
2L = 40 - 2W
L = (40 - 2W) / 2
L = 20 - W
Now, we have an expression for L in terms of W.
To find the area of the garden plot, we can use the formula for the area of a rectangle:
A = L * W
We can substitute the expression for L in terms of W into the area equation to get a function for the area of the garden plot:
A = (20 - W) * W
Simplifying this equation, we get:
A = 20W - W^2
So, the area of the garden plot is a function of the width of the rectangle, given by A = 20W - W^2.