A Thunderbird leaves at 12:00pm constantly traveling at 20mph. At 4:30pm a Jaguar leaves from the same place on the same path and reaches the Thunderbird at 9:30pm. How much faster was the Jaguar constantly traveling?
The Jaguar caught-up in 5 hous. Therefore, it was on the road 5 hours.
The Thunderbird left4.5 hours earlier.
Therefore, it was on the road 9.5 hours.
Both vehicles had traveled the same
distance:
d1 = d2.
20mi/h * 9.5h = V * 5,
190 = 5V,
V = 38mi/h. = Speed of the Jaguar.