# geometry

If the edges of the base of a rectangular prism are 8cm and 6cm, and the diagonal is 10--square root of 2, what is the volume of the solid?

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asked by L.D.
1. diagonal of rectangular base = sqrt(8^2+6^2) = sqrt 100 = 10

so if height is h
h^2 + 10^2 = (10 sqrt 2)^2 = 200
h^2 = 200 - 100 = 100
h = 10
6*8*10 = ?

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posted by Damon

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