a tree casts a 25 foot shadow on a sunny day if the angle of elevation from the tip of the shadow to the top of the tree 32 degrees, what is the height of the tree to the nearest thenth of a foot?

tan 32 = h/32

sorry

tan 32 = h/25

thank you :)

13.2

tan[32degrees]=y/25

.6248693519=y/25
15.6

To find the height of the tree, you can use the trigonometric relationship between the angle of elevation, the height of the tree, and the length of the shadow. In this case, you are given the length of the shadow (25 feet) and the angle of elevation (32 degrees).

We can use the tangent function, which relates the angle of elevation to the ratio of the height of the tree to the length of the shadow:

tan(angle of elevation) = (height of the tree) / (length of the shadow)

Using this equation, we can solve for the height of the tree:

tan(32 degrees) = (height of the tree) / (25 feet)

To find the height of the tree, we can rearrange the equation as follows:

(height of the tree) = (tan(32 degrees)) * (25 feet)

Now, let's calculate the height of the tree:

(height of the tree) = tan(32 degrees) * 25 feet
(height of the tree) ≈ 0.6249 * 25 feet
(height of the tree) ≈ 15.62 feet

Therefore, the height of the tree is approximately 15.62 feet, rounded to the nearest tenth of a foot.