36.00mL of KMnO4 is required to oxidize 25.00mL of 0.02932M Na2C2O4 solution. what is the concentration ofKMnO4?

Do I just use C1V1=C2V2?

Thank You

Yes, you can use the formula C1V1 = C2V2 (where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume) to solve this problem.

Given:

C1 = unknown concentration of KMnO4
V1 = 36.00 mL
C2 = 0.02932 M (concentration of Na2C2O4)
V2 = 25.00 mL

To find the concentration of KMnO4 (C1), rearrange the formula:

C1 = (C2V2) / V1

Substitute the given values:

C1 = (0.02932 M * 25.00 mL) / 36.00 mL

Now calculate:

C1 = 0.01612 M

So, the concentration of KMnO4 is approximately 0.01612 M.