Complete the identity sin theta / cos theta + cos theta / sin theta = ?
Do you mean
(sin theta/cos theta) + (cos theta/sin theta) ?
That would equal tan x + cot x = tan x + (1/tan x) = (tan^2 x + 1)/ tan x
I don't see any way to further simplify it.
1/(cosx)(sinx) or
sin^2x+cos^2x/(cosx)(sinx)
How do u find the standard form of the quation of the specified circle?? center =(0,1/3) and radius = 1/3
How do u find the standard form of the quation of the specified circle?? center =(0,1/3) and radius = 1/3
(x-0)^2+(y-1/3)^2=1/3^2
FIND DOMAIN
F(X)=5Xsquared + 2X-1
AND DIFFERENCE QUOTIENT AND SIMPLIFY
F(X)=Xcubed
F(X)=4/X+1
if f(x)=x^3-2x-1,then f(-2)=
There is a sign that is 10ft on one side and 15ft on the other side (from the ground to the base of the sign), the billboard itself is 20ft.
The painter brings a 25ft ladder in length.
If the patch of ground 10ft from the base of the sign is used, at what point will the ladder touch the sign? Need two answers. 1st - length if measured from the ground and 2nd - if measured from the bottom of the sign.
What are Maximum and Minimum functions?
Hi i want to know about the history of calculas and some books about this
i have problem as shown under.
3x-2y = 6 and it says graph it label the origin x- and y-intercepts as triangle OPQ respectively. Find the area of triangle OPQ.
plz help me out asap
To solve the equation 3x - 2y = 6 and graph it, we can rearrange the equation to solve for y:
3x - 2y = 6
-2y = -3x + 6
y = (3/2)x - 3
Now we have the equation in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept. In this case, the slope is 3/2 and the y-intercept is -3.
To graph the equation, we can plot the y-intercept first, which is the point (0, -3). Next, we can use the slope of 3/2 to find more points on the line. For example, if we move up 3 units and to the right 2 units from the y-intercept, we get the point (2, 0). We can continue this process to find more points and draw a line through them.
To find the x-intercept, we can set y = 0 in the equation:
0 = (3/2)x - 3
(3/2)x = 3
x = 2
So the x-intercept is (2, 0).
To find the area of triangle OPQ, we can use the formula for the area of a triangle: A = (1/2) * base * height.
The base of triangle OPQ is the distance between the x-intercept and the origin, which is 2 units. The height is the distance between the y-intercept and the origin, which is 3 units.
Therefore, the area of triangle OPQ is A = (1/2) * 2 * 3 = 3 square units.