the chapter is on electric fields and forces and I cannot figure these 3 answers out:
Matt forgot to put the fabric softener in the wash. As his socks tumbled in the dryer, they became charged. If a small piece of lint with a charge of +1.25 E -19 C is attracted to the socks by a force of 3.0 E -9 N, what is the magnitude of the electric field at this location?
Suppose an electric field with a magnitude of 2.8 E 4 N/C at a certain location, points due south. If a charge of -4.0 E -6 C is brought to the location, what is the electrostatic force that acts on this charge?
http://www.jiskha.com/display.cgi?id=1306034094 what is is about force equals charge times Electic Field strength that you don't understand?
To find the magnitude of the electric field, we can use the equation:
Electric field (E) = Force (F) / Charge (q)
In the given problem, we are given the force and the charge. We need to rearrange the equation to solve for the electric field.
1. For the first problem:
Force (F) = 3.0 E -9 N
Charge (q) = +1.25 E -19 C
By plugging in the given values into the equation and solving for the electric field (E), we get:
E = F / q
E = (3.0 E -9 N) / (+1.25 E -19 C)
E = (3.0 / 1.25) E (-9 - (-19)) N/C
E = 2.4 E 10 N/C
Therefore, the magnitude of the electric field at this location is 2.4 E 10 N/C.
2. For the second problem:
Electric field (E) = 2.8 E 4 N/C
Charge (q) = -4.0 E -6 C
In this problem, we are given the electric field and the charge. We need to use the equation to calculate the force (F).
F = E * q
F = (2.8 E 4 N/C) * (-4.0 E -6 C)
F = (2.8 * -4.0) E (4 + (-6)) N
F = -11.2 E -2 N
Therefore, the electrostatic force that acts on the charge is -11.2 E -2 N.