The magnitude of a force pulling a box 5 m at a 20 degree angle from horizontal is 68N. How much work is done on the box?

plz help me solve this!

That is not the whole problem. To figure out how much work is done we have to know how far the box is pulled.

You did not say but I assume the box is being pulled horizontally so the force in the direction of motion is
68 cos 20 = 63.9 Newtons
The work done by the force in Joules is 63.9 times the distance moved in meters.

Multiply the force component Damon provided by the 5 m distance moved and you will have the work done, in Joules

To solve this problem, we can use the formula for work done, which is given by:

Work = Force * Distance * cos(theta)

In this case, the force is 68 N, the distance is 5 m, and the angle from the horizontal is 20 degrees.

First, we need to find the horizontal component of the force, which is given by:

Force_horizontal = Force * cos(theta)

So, we can calculate the horizontal component of the force as follows:

Force_horizontal = 68 N * cos(20 degrees) = 68 N * 0.9397 = 63.82 N

Next, we can substitute the horizontal force and the distance into the work formula:

Work = Force_horizontal * Distance

Work = 63.82 N * 5 m = 319.1 Joules

Therefore, the work done on the box is 319.1 Joules.