# physic

A "seconds pendulum" is one that moves through its equilibrium position once each second. (The period of the pendulum is precisely 2.000 s.) The length of a seconds pendulum is 0.9928 m at Tokyo and 0.9943 m at Cambridge, England. What is the ratio of the free-fall accelerations at these two locations?
(g Cambridge / g Tokyo)?
any help?

1. 👍 0
2. 👎 0
3. 👁 298
1. T=2PI(L/g)

so the ratio is ...

1=sqrt(.9928/gtokio*gengland/.9943)

squaring both sides..

gengland/gtokyo= .9943/.9928

1. 👍 0
2. 👎 0
2. awesome, Thanks a lot...

1. 👍 0
2. 👎 0
posted by sisca

## Similar Questions

1. ### Physics

A "seconds pendulum" is one that moves through its equilibrium position once each second. (The period of the pendulum is precisely 2.000 s.) The length of a seconds pendulum is 0.9925 m at Tokyo and 0.9948 m at Cambridge, England.

asked by Zandy on October 30, 2014
2. ### Calculus application of sin function

a horizontal position of the pendulum of a grandfather clock can be modelled by h(t)=Acos(2(pi)t/T), where A is amplitude of the pendulum in meters, t is time in seconds, and T is the period of the pendulum, in seconds. If the

asked by Matt on November 25, 2016
3. ### Math - Linear Equations

"the period of a pendulum, T (in seconds) varies directly with the square root of the length of the pendulum, L (in centimeters)". Given that a pendulum of length 9cm has a period of 0.63 seconds, find: a) The period of a pendulum

asked by Kiirsty on May 24, 2014
4. ### math

The formula T=2*pi*sqrt[L/g] gives the period of a pendulum of length l feet. The period P is the number of seconds it takes for the pendulum to swing back and forth once. Suppose we want a pendulum to complete three periods in 2

asked by Gabi on April 10, 2011
5. ### math

The formula T=2*pi*sqrt[L/32] gives the period of a pendulum of length l feet. The period P is the number of seconds it takes for the pendulum to swing back and forth once. Suppose we want a pendulum to complete three periods in 2

asked by Gabi on April 11, 2011
6. ### physics

The period of a simple pendulum is measured to be 4.0 seconds in a frame of reference. Which of the following is correct when the period of the pendulum is measured by an observer moving with 0.4 times the speed of the light?

asked by ashley -- on April 30, 2011
7. ### physics

The period of a simple pendulum is measured to be 4.0 seconds in a frame of reference. Which of the following is correct when the period of the pendulum is measured by an observer moving with 0.4 times the speed of the light?

asked by ashley -- on April 30, 2011
8. ### physics

The period of a simple pendulum is measured to be 4.0 seconds in a frame of reference. Which of the following is correct when the period of the pendulum is measured by an observer moving with half the speed of the light? Choose