Complete the following radioactive decay problem.

234 4
U ---> He+
92 2

how do i do this?

help me

PLEASEEEEEEE

To complete the given radioactive decay problem, you need to balance the nuclear equation by ensuring that the sum of the atomic numbers (protons) and the sum of the mass numbers (protons and neutrons) are equal on both sides of the equation.

Let's break down the given reaction:

The parent nuclide (92U or Uranium-234) is undergoing alpha decay, where it emits an alpha particle (2He) and transforms into a daughter nuclide.

To balance this equation, you need to ensure the total number of protons and mass numbers on both sides are equal. Here's how you can do it step-by-step:

1. Start with the parent nuclide on the left side: 234U92.
2. The alpha particle (4He2) consists of 2 protons and 2 neutrons, so write it on the right side: 4He2.
3. As alpha particles have 2 protons, this means the resulting daughter nuclide should have 2 protons less than the parent nuclide.
=> The daughter nuclide will have an atomic number (proton number) of 92 - 2 = 90.
4. The mass number (protons + neutrons) on the left side is 234 + 0 = 234.
5. The mass number on the right side is 4 + 230 (2 from protons in He plus 228 from remaining protons and neutrons in daughter nuclide).
=> The daughter nuclide will have a mass number of 234 - 4 = 230.
6. Combine the atomic number and the element symbol for the daughter nuclide: 230Th90.

Therefore, the balanced equation for the given radioactive decay is:

234U92 ---> 4He2 + 230Th90

i need help

It's like a math problem.

234 = 4 + ___

92 = 2 + ___

The top number = mass number = number of protons + number of neutrons

The bottom number = number of protons

Find the element that correspond to the top and bottom number.