@ 20 Celsius - 22g CuSO4 / 100g H2O
@ 40 Celsius- 42g CuSO4 / 100g H2O
Using this, answer whether these are saturated or unsaturated
@ 40 Celsius is 5g CuSO4 / 10g H2O
@ 40 Celsius is 99g CuSO4 / 250g H2)
I was told that the first one is unsaturated and the second one is saturated but...I come up the opposite of what I was told....Help please!
Also, I looking for someone to tell me if the answers are correct that I came up with to these questions.
Can anyone tell me if I am right on these?
Calculate the amount of solute needed to make each of the solutions
225g of 10% (m/m) K2CO3 solution
Answer: 22.5g K2CO3
0.50kg of 18% (m/m) KOH solution
Answer: 90g KOH
To determine whether a solution is saturated or unsaturated, you need to compare the solute concentration in the solution with the maximum solute concentration that can be dissolved in that particular solvent at a given temperature. The maximum solute concentration is known as the solubility.
Based on the given information:
1. @ 20 Celsius - 22g CuSO4 / 100g H2O
The solubility of CuSO4 in water at 20 Celsius is 22g/100g H2O. Since the actual concentration matches the solubility, the solution is saturated.
2. @ 40 Celsius - 42g CuSO4 / 100g H2O
The solubility of CuSO4 in water at 40 Celsius is 42g/100g H2O. The actual concentration is less than the solubility, so the solution is unsaturated.
3. @ 40 Celsius - 5g CuSO4 / 10g H2O
The solubility of CuSO4 in water at 40 Celsius is 42g/100g H2O. The actual concentration is less than the solubility, so the solution is unsaturated.
4. @ 40 Celsius - 99g CuSO4 / 250g H2O
The solubility of CuSO4 in water at 40 Celsius is 42g/100g H2O. The actual concentration is higher than the solubility, so the solution is supersaturated.
Regarding the calculations for the amount of solute needed to make the solutions:
1. 225g of 10% (m/m) K2CO3 solution
To calculate the amount of solute (K2CO3) needed, you multiply the mass of the solution by the percentage of the solute:
225g x 0.10 = 22.5g
So, your answer of 22.5g K2CO3 is correct.
2. 0.50kg of 18% (m/m) KOH solution
Similarly, you multiply the mass of the solution by the percentage of the solute:
0.50kg x 0.18 = 90g
Hence, your answer of 90g KOH is also correct.
To determine if a solution is saturated or unsaturated, you need to compare the actual concentration of the solute to the maximum possible concentration at that temperature.
Let's go through each scenario:
1. @ 20 degrees Celsius - 22g CuSO4 / 100g H2O
To determine if this solution is saturated or unsaturated, we need to know the solubility of CuSO4 at 20 degrees Celsius. If the solubility of CuSO4 at this temperature is higher than 22g/100g H2O, then the solution is unsaturated. If the solubility is lower, then the solution is saturated.
2. @ 40 degrees Celsius - 42g CuSO4 / 100g H2O
Similar to the previous scenario, we need to compare the solubility of CuSO4 at 40 degrees Celsius to 42g/100g H2O. If the solubility is higher than 42g/100g H2O, then the solution is unsaturated. If the solubility is lower, then the solution is saturated.
Regarding your confusion about the second scenario, it seems there might be a misunderstanding. The statement you mentioned says "@ 40 degrees Celsius is 5g CuSO4 / 10g H2O," but later you mentioned "@ 40 degrees Celsius is 99g CuSO4 / 250g H2O." These values conflict, so it's unclear which one is accurate.
Now let's move on to solving the solute amount calculations:
1. 225g of 10% (m/m) K2CO3 solution
10% (m/m) means that 10g of K2CO3 is present in 100g of the solution. To find the amount of K2CO3 in 225g of the solution, we can set up a proportion:
10g / 100g = x / 225g
Cross-multiplying:
100g * x = 10g * 225g
Dividing both sides by 100:
x = (10g * 225) / 100
Simplifying:
x = 22.5g
So, the correct answer is 22.5g K2CO3.
2. 0.50kg of 18% (m/m) KOH solution
18% (m/m) means 18g of KOH is present in 100g of the solution. We need to find the amount of KOH in 0.50kg (500g) of the solution. Again, we can set up a proportion:
18g / 100g = x / 500g
Cross-multiplying:
100g * x = 18g * 500g
Dividing both sides by 100:
x = (18g * 500) / 100
Simplifying:
x = 90g
So, the correct answer is 90g KOH.
In summary, if the information about the solubility values is provided, you can determine the saturation of the solutions at the given temperatures. Additionally, based on the given calculations for solute amount, your answers of 22.5g K2CO3 and 90g KOH are correct.