The function h is is defined below.
h(x)=48x^2+ 12x - 16
Find all values of x that are NOT in the domain of h.
If there is more than one value, separate them with commas.
I'm lost.
The function h is is defined below
h(x)=(x+6)/(x^2+9x+8)
Find all values of x that are NOT in the domain of h.
If there is more than one value, separate them with commas.
This is a rational function.
The domain is in the Real numbers, i.e. (-∞,∞) except where the denominator becomes zero.
Therefore solving for
(x^2+9x+8) = 0
(x+8)(x+1) = 0
or x=-8, or x=-1.
Therefore the values of x that do not belong to the domain of f(x) is -8 and -1.
To find the values of x that are not in the domain of the function h(x) = 48x^2 + 12x - 16, we need to identify any values that would result in undefined operations.
In this case, the only operation we have is raising x to the power of 2. Since any real number can be squared, there are no restrictions on the domain due to this operation.
Therefore, the function h(x) is defined for all real numbers, and there are no values of x that are not in the domain of h.
To find the values of x that are not in the domain of the function h(x), we need to determine any restrictions on x that would make the function undefined.
In general, there are two types of restrictions that can make a function undefined:
1. Division by zero: If the function involves dividing by zero, then that value of x would be restricted.
2. Taking the square root of a negative number: If the function involves taking the square root of a negative number, then that value of x would be restricted.
Looking at the given function h(x) = 48x^2 + 12x - 16, we can see that it does not involve division by zero and there are no square roots involved. Therefore, there are no restrictions on the domain of this function. In other words, every real number is in the domain of h(x).
Therefore, the values of x that are not in the domain of h(x) do not exist, and there are no values to list.