The sides of a triangular lot are represented by x, 2x, and 3x + 2. Find each side if the perimeter is 362 feet.
O my, x=60, not 6.. My fault for overlooking that.
The three sides would be,
60
120
182
*Sorry again
To find the lengths of the sides of the triangular lot, we can use the fact that the perimeter of a triangle is the sum of its side lengths.
So, let's add the side lengths of the triangle:
x + 2x + 3x + 2 = 362
Combining like terms:
6x + 2 = 362
Next, let's isolate the variable x by subtracting 2 from both sides of the equation:
6x = 362 - 2
6x = 360
Now, we can solve for x by dividing both sides of the equation by 6:
x = 360 / 6
x = 60
So, one side of the triangular lot is x = 60 feet.
To find the lengths of the other sides, we substitute this value back into the expressions for the sides:
Length of the second side = 2x = 2 * 60 = 120 feet
Length of the third side = 3x + 2 = 3 * 60 + 2 = 182 feet
Therefore, the lengths of the sides of the triangular lot are:
- First side: 60 feet,
- Second side: 120 feet,
- Third side: 182 feet.
To find perimeter, you add up all the sides.
So, your equation would be:
x+2x+3x+2=362
Combine like terms:
6x+2=362
Solve to get x by itself by subtracting 2.
6x=360
Divide by 6
x=6
To find each side, substitute 6 in for x for each of the expressions, x, 2x, and 3x+2
Side one would be 6 feet
Side two would be 12 feet because 6(2) is 12
Side three would be 20 feet because 6(3) is 18 and adding 2 would give you 20.