What is the Net Ionic Equation for the following:

a.) NH4Br, NaOH

b.) Li2CO3, HClO4

c.)Pb(NO3)2, Kl

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To find the net ionic equation, we need to first write the balanced molecular equation and then convert it to the net ionic equation by writing only the species that participate in the chemical reaction.

a.) NH4Br, NaOH:

Step 1: Write the balanced molecular equation:
NH4Br + NaOH --> NH3 + H2O + NaBr

Step 2: Identify soluble and insoluble compounds:
In this case, NH3 (ammonia), H2O (water), and NaBr (sodium bromide) are soluble.

Step 3: Write the net ionic equation:
NH4+ + OH- --> NH3 + H2O

b.) Li2CO3, HClO4:

Step 1: Write the balanced molecular equation:
Li2CO3 + 2HClO4 --> 2LiClO4 + H2O + CO2

Step 2: Identify soluble and insoluble compounds:
In this case, LiClO4 (lithium perchlorate), H2O (water), and CO2 (carbon dioxide) are soluble.

Step 3: Write the net ionic equation:
No net ionic equation can be formed in this case as all the species that participate in the reaction are soluble and dissociate completely.

c.) Pb(NO3)2, KI:

Step 1: Write the balanced molecular equation:
Pb(NO3)2 + 2KI --> PbI2 + 2KNO3

Step 2: Identify soluble and insoluble compounds:
In this case, PbI2 (lead iodide) is insoluble and will form a precipitate.

Step 3: Write the net ionic equation:
Pb2+ + 2I- --> PbI2

In summary, the net ionic equations for the given reactions are:
a.) NH4+ + OH- --> NH3 + H2O
b.) No net ionic equation can be formed.
c.) Pb2+ + 2I- --> PbI2