The function h is defined by h(x)=x^(2)-x.

Find h(2x).

(2x)^2-2x=4x^2-2x

Substitute 2x for x into the function, which would leave you:

h(x)=(2x)^2-2x

Factor out a 2x.

H(x)=2x(x-1) then set 2x and x-1 both equal to 0.

2x=0 x-1=0

x= 0 x=1

My money is on bobpursley, big time!

Thanks I agree Reiny

To find h(2x), we need to substitute the value 2x into the function h(x) and simplify the expression.

Given that h(x) is defined as h(x) = x^2 - x, we substitute 2x into the function:

h(2x) = (2x)^2 - 2x

Now we simplify the expression:

h(2x) = 4x^2 - 2x

So, h(2x) is equal to 4x^2 - 2x.