a triangular road sign has a height of 8 feet and a base of 16.5 feet. How much larger in ares is this sign than one with a height of 4 feet and a base of 8.25 feet?
Please explain fully and show how you got the answer.
i'm rather in a rush so could you please answer my question and explain? thank you
You know the area of a triangle is A=1/2bh. So, to find how much larger the 2nd triangle is compared to the first, you would first find the area of the first triangle.
Area of 1st triangle:
A=1/2bh
A=1/2(16.5)(8)
A=66 feet
Then find the area of the second triangle:
A=1/2bh
A=1/2(8.25)(4)
A=16.5 feet
You know the two areas, so therefore you would take the difference of these two numbers to come to a total of 49.5 feet.
It would be 49.5 feet larger.
thank you!!!
To find the difference in area between two triangular road signs, we need to calculate the area of each sign and then find the difference between them.
The formula for the area of a triangle is given by:
Area = (base * height) / 2
Let's calculate the area of the first triangular road sign with a height of 8 feet and a base of 16.5 feet:
Area of first sign = (16.5 * 8) / 2 = 132 square feet
Now, let's calculate the area of the second triangular road sign with a height of 4 feet and a base of 8.25 feet:
Area of second sign = (8.25 * 4) / 2 = 16.5 square feet
To find the difference in area, subtract the area of the second sign from the area of the first sign:
Difference in area = Area of first sign - Area of second sign
= 132 - 16.5
= 115.5 square feet
Therefore, the triangular road sign with a height of 8 feet and a base of 16.5 feet is 115.5 square feet larger than the sign with a height of 4 feet and a base of 8.25 feet.