# trigonometry

express secA in terms of cotA?
can you pleas say how to solve this??

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1. are you sure it wasn't cscA expressed in terms of cotA ?

If so, then
form cos^2 A + cos^2A = 1
divide by sin^2A
cot^2A + 1 = csc^2A
cscA = √(cot^2A + 1)

The way you have it, would make a very messy conversion.

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posted by Reiny

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