1. Questions

factoring

Factor x3 + 9x2 + 27x + 27
Factor 8a3 + 60a2b + 150 ab2+ 125b3

I tried doing them, but I just don't get how; perfect squares didn't work and neither did decomposition... someone please help me.

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Chujung

  1. Factor the following:
    a)x4 + 11x2 + 30
    b)x4 – 7x2y + 12y2
    c)x6 - 3x3 -54
    d)3(x – 5)2 + 27(x – 5) – 66

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    Chujung

  2. <<Factor x^3 + 9x^2 + 27x + 27 >>
    There is no simple general formula for solving cubic equations or factoring cubic poynomials. First look for one root of
    x^3 + 9x^2 + 27x + 27 = 0
    by graphing or trial and error.
    One root is x = -3. That means that x+3 is one of the factors of
    x^3 + 9x^2 + 27x + 27. Now use long division to get the quadratic factor. Divide x^3 + 9x^2 + 27x + 27 by (x+3), which will give you (x^2 + 6x + 9). That can be factored to (x+3)^2

    The factored form is thus
    (x+3)^3

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    drwls

  4. oh, okay, thanks!

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    Chujung

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